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What is an equation of the line that passes through the point (7,-7) and is perpendicular to the line x-2y=2x−2y=2?

Respuesta :

amarelydia73

Answer:

x-2y=2x-2y=2

7-2×(-7)=2×7-2×(-7)=2

7-(-14)=14-(-14)=2

7+14=14+14=2

21=28=2

Answer:

y=−2x+7

Step-by-step explanation:

The other moron doesn't understand simple math.

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