Answer:
0.9398 = 93.98% probability that the student is not of Asian origin.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Business student
Event B: Not of Asian origin.
Probability that the student is an undergraduate majoring in business.
15% of 13%(Of Asian origin).
35% of 100 - 13 = 87%(Not of Asian origin). So
[tex]P(A) = 0.15*0.13 + 0.35*0.87 = 0.324[/tex]
Business student and not of Asian origin:
35% of 87%. So
[tex]P(A \cap B) = 0.35*0.87 = 0.3045[/tex]
One undergraduate student majoring in Business is randomly selected from this university. Find the probability that the student is not of Asian origin.
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3045}{0.324} = 0.9398[/tex]
0.9398 = 93.98% probability that the student is not of Asian origin.
