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No need to use pi for this problem! So we're finding the area of a trapezoid. It's made up of: a square with length and width 2, and two triangles with a base 2 and height 2.

Area of a triangle formula is [tex]A = \frac{1}{2} B\cdot h[/tex]

[tex]A = \frac{1}{2}\cdot2\cdot 2[/tex]

[tex]A = \frac{1}{2}\cdot 4[/tex]

[tex]A = 2[/tex] units^2

And since the two triangles are the same, the other triangle has the same area: 2 units^2

For the square we can use [tex]A = l\cdot w[/tex]  

[tex]A = 2 \cdot 2[/tex]

[tex]A = 4[/tex]

Combine the areas: the total area is 2 + 2 + 4 , = 8 units^2

puzzledpusheen

Answer:

8 units²

Step-by-step explanation:

In order to find the area of this trapezoid, you can apply the formula for the area of a trapezoid: ([tex]b_{1}[/tex] + [tex]b_{2}[/tex]) × h/2

In the equation, you already know base one (2) and the height (2), but base two isn't given. To find the length of the whole base, you need the length of the other side of the square: You can tell that it is two because the two given sides of the square are 2.

Since you now know that the length of the missing side of the base is 2, you can add the three values given to get the base length:

2 + 2 + 2 = 6

Now, you have all the information needed to find the area of the trapezoid. Input them all into the equation:

([tex]b_{1}[/tex] + [tex]b_{2}[/tex])*h/2 where [tex]b_{1}[/tex] is 2, [tex]b_{2}[/tex] is 6, and h is 2,

(2 + 6) × 2/2

= 8 × 1

= 8 units²

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