Answer:
Final Temp = 23.92°C
Explanation:
ΔH(total) = (m·c·ΔT)ice + (m·ΔH(f))melt'g + (m·c·ΔT)water
2182.5j = (5g)(2.092j/g·°C)(1°C) + (5g)(334.56j/g) + (5g)(4.184j/g·°C)(ΔT)
(2182.5 - 10.46 - 1672.8)j = 20.92j/°C·ΔT
ΔT = (2182.5 - 10.46 - 1672.8)j / 20.92j/°C = 23.92°C
Since the melting ice starts and ends at 0°C and is then warmed to 23.92°C then the temperature change is also the final temp of the water based upon given energy input values.
