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50 POINTS FOR WHO EVER ANSWERS THIS
Part C: Write an expression for the area of square 4 by combining the areas of the four triangles and the two squares.

Part D: Write an expression for the area of square 5 by combining the areas of the four triangles and the one square.

Part E: Since the areas of square 4 and square 5 are the same, set the two expressions equal.

Part F: Which term is on both sides of the equal sign? Since it’s on both sides of the equal sign, you can cancel it out. What is the expression after canceling out the common term?

Part G:What does the equation show after you cancel out a common term?

Thank you!!!!

50 POINTS FOR WHO EVER ANSWERS THIS Part C Write an expression for the area of square 4 by combining the areas of the four triangles and the two squares Part D class=

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emy0san

The area of Square 4 is [tex]a^2+2ab+b^2[/tex].

The area of Square 5 is [tex]2ab+c^2[/tex].

Setting them equal to one another ([tex]a^2+2ab+b^2=2ab+c^2[/tex]) and simplifying yields that [tex]a^2+b^2=c^2[/tex] (note that [tex]2ab[/tex] is what they have in common), which is Pythagoras' theorem.

roxierocket123

Answer: part A

The relationship between the areas of the three squares is that square A plus square B equals the area of square C.

part E

(4y)^2 = (5x)^2   and      25x^2 - 16y^2 = 0          

part F

(4y)=(5x)

25x-16y=0

 

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