Answer:
The rock will be be 5 meters from ground level at time = 3.713 seconds
Step-by-step explanation:
As we know-
[tex]s(t) = -4.9 * t^2 + v_0t + s_0[/tex]
V0 = velocity
S0 = height above ground when thrown
Substituting the given values, we get -
[tex]9 = -4.9* t^2 + 12 * t +32\\-4.9*t^2 +12*t + 23 = 0[/tex]
As per the formula
[tex]t = \frac{-12+ \sqrt{12^2 -4*(-4.9)*23} }{(2*(-4.9)} \\t = 3.713[/tex]
The rock will be be 5 meters from ground level at time = 3.713 seconds
