Answer:
Step-by-step explanation:
Given : [tex](x_1,y_1)=(-3,2)[/tex]
[tex]m=\frac{2}{3}[/tex]
Solution:
Equation of line:[tex]y-y_1 = m(x-x_1)[/tex]
Substituting the given values
⇒[tex]y-2= \frac{2}{3}(x-[-3])[/tex]
⇒[tex]y-2= \frac{2}{3}(x+3)[/tex] --A
⇒ [tex]3y-6= 2x+6[/tex]
⇒ [tex]2x-3y = -6-6[/tex]
⇒[tex]2x-3y =-12[/tex] ---B
⇒[tex]2x+12 =3y[/tex]
⇒ [tex]\frac{2x+12}{3} =y[/tex]
⇒ [tex]\frac{2}{3}x+4 =y[/tex] ---C
Hence Equation A ,B and C are the correct equations
