Respuesta :
b
b357
Answer:
2Fe +3 H2SO4 Fe2(SO4)3 + 3H2
2*56g. 3*98g➔400g. +6g
we have
2*56 g of Fe gives 400g of iron (III ) sulfate
now
100g of Fe gives=400/112*100=357g of iron (III ) sulfate
b
b357
Answer:
2Fe +3 H2SO4 Fe2(SO4)3 + 3H2
2*56g. 3*98g➔400g. +6g
we have
2*56 g of Fe gives 400g of iron (III ) sulfate
now
100g of Fe gives=400/112*100=357g of iron (III ) sulfate