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PLEASE HELP. requires 35 mL of NaOH(aq) to neutralize
10. mL of 0.10 M HCl(aq). The concentration of the NaOH(aq) is

Respuesta :

samueladesida43

Answer:

0.0286M

Explanation:

Using the formula as follows:

CaVa = CbVb

Where;

Ca = concentration of HCl acid (M)

Cb = concentration of NaOH base (M)

Va = volume of HCl acid (mL)

Vb = volume of NaOH base (mL)

According to the information provided in this question;

Ca = 0.10 M

Cb = ?

Va = 10mL

Vb = 35mL

Using CaVa = CbVb

Cb = CaVa/Vb

Cb = (0.10 × 10) ÷ 35

Cb = 1 ÷ 35

Cb = 0.0286M

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