Answer:
A: x = 0
B: x = All real numbers
Step-by-step explanation:
A.
Any number to the power of (0) equals one. This applies true for the given situation; one is given an expression which is as follows;
[tex](6^2)^x=1[/tex]
Simplifying that will result in;
[tex]36^x=1[/tex]
As stated above, any number to the power of (0) equals (1), thus (x) must equal (0) for this equation to hold true.
[tex]36^0=1\\x=0[/tex]
B.
As stated in part (A), any number to the power (0) equals (1). Therefore, when given the following expression;
[tex](6^0)^x=1[/tex]
One can simplify that;
[tex]1^x=1[/tex]
However, (1) to any degree still equals (1). Thus, (x) can be any value, and the equation will still hold true.
[tex]x=All\ real \ numbers[/tex]
