Respuesta :
Answer:
[tex]i)36\\ii)7[/tex]
Step-by-step explanation:
[tex]i) As\ our\ first\ expression,\ we\ have:\\ab^2\\Substituting\ a=4, b=-3:\\ab^2=4*(-3)^2=4*-3*-3=4*9=36\\ii)Next,\ we\ have:\\(a-b)(a+b)\\Hence,\\Substituting\ a=4,\ b=-3:\\(a-b)(a+b)=(4-3)(4+3)=1*7=7\\Note:\\You\ can\ also\ use\ the\ algebraic\ identity: (a+b)(a-b)=a^2-b^2[/tex]
Answer:
Given that, a = 4 and b = -3
Now,
- i) ab² = (4)(-3)² = (4)(9) = 36
- ii) (a-b)(a+b) = (a²-b²) = {(4)²-(-3)²} = (16-9) = 7