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41. A bag contains 20 balls numbered from 1 to 20.
Two balls are selected at the same time from the bag.
What is the probability that the two numbers selected do NOT differ by 12?

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168136

Answer: 77/95 chance

Step-by-step explanation: There are 8+7+6+5+4+3+2+1 = 36 choices that differ by 12 or more, so the probability they differ by 12 or more is 36/190 = 18/95. So the probability that they do not differ by 12 or more is 1 - 18/95 = 77/95. Brainliest please?

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