a person with a mass of 75kg jumps on the trampoline the trampoline creates a fprce of 375n on them what is the acceleration of the person after they leave the trampoline​

Respuesta :

Newton's second law allows calculating the response for the person's acceleration while leaving the trampoline is:

            -4.8 m / s²

Newton's second law says that the net force is proportional to the product of the mass and the acceleration of the body

            F = m a

Where the bold letters indicate vectors, F is the force, m the masses and the acceleration

The free body diagram is a diagram of the forces without the details of the body, in the attached we can see the free body diagram for this system

 

               [tex]F_t[/tex] -W = m a

Whera [tex]F_t[/tex] is the trampoline force

Body weight is

                W = mg

We substitute

              [tex]F_t[/tex] - mg = ma

              a =[tex]\frac{F_t - m g}{m}[/tex]

Let's calculate

              a = [tex]\frac{375 - 75 \ 9.8 }{75}[/tex]

              a = -4.8 m / s²

The negative sign indicates that the acceleration is directed downward.

In conclusion using Newton's second law we can calculate the acceleration of the person while leaving the trampoline is

            -4.8 m / s²

Learn more here:  brainly.com/question/19860811

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