be9zashorsey be9zashorsey
  • 01-01-2017
  • Mathematics
contestada

If f(x) = (x - 3)2 , find all values of x for which f(x) = 36.

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olemakpadu
olemakpadu olemakpadu
  • 01-01-2017
f(x) = (x - 3)²,

For f(x) = 36

(x - 3)² = 36

Take the square root of both sides

√(x - 3)² = √36

(x - 3) = +6 or - 6

x = 3 + 6   or   3 - 6

x =9 or - 3

The values of x are -3 and 9.
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