Answer:
[tex]\frac{10}{21}[/tex]
Step-by-step explanation:
Total number of balls = [tex](2 + 3 + 2) = 7[/tex]
Let S be the sample space.
Then, n(S) = Number of ways of drawing 2 balls out of 7
= ⁷ C₂
= [tex]\frac{(7*6)}{(2*1)}[/tex]
=21
Let E = Event of drawing 2 balls, none of which is blue.
∴n(E)= Number of ways of drawing 2 balls out of (2 + 3) balls.
= ⁵ C₂
= [tex]\frac{(5*4)}{(2*1)}[/tex]
= 10
∴ P (E) = [tex]\frac{n(E)}{n(S)} =\frac{10}{21}[/tex]
