Respuesta :
Keplers 3rd law tells us that the square of the orbital period of a planet is proportional to the cube of the semi-major axis if the planet.
p^2 = a^3
So if the orbital period is 29.46 years, then:
(29.46)^2 = a^3
867.8916 = a^3
9.54 au = a
So the average distance between Saturn and the Sun is 9.54 au
au = atronomical units.
idk if i did this right, its been a while
p^2 = a^3
So if the orbital period is 29.46 years, then:
(29.46)^2 = a^3
867.8916 = a^3
9.54 au = a
So the average distance between Saturn and the Sun is 9.54 au
au = atronomical units.
idk if i did this right, its been a while
Answer:
9.54 AU
Explanation:
Kepler's Third law of motion would be used. According to it, the square of orbital period (P) is proportional to the cube of average distance (a).
P² = a³
where, P is in years and a is in AU.
Given P = 29.46 years
Substitute the values as follows:
(29.46)² = a³
[tex]\Rightarrow a= \sqrt[3]{867.9}=9.54 AU[/tex]
Thus, the average distance between the Sun and Saturn is 9.54 AU.