The height of the plane at that time is 1.1 miles
The distance of the plane's path is 10.1 miles
The situation forms a right angle triangle.
Using trigonometric ratio,
tan 6° = opposite / adjacent
The height of the plane is the opposite side of the triangle. The adjacent
side is the distance travelled horizontally. Therefore,
tan 6° = h / 10
cross multiply
h = 10 tan 6°
h = 10 × 0.10510423526
h = 1.05104235266
height of the plane at that time = 1.1 miles
The distance of the plane path is the hypotenuse of the triangle formed.
Therefore,
c² = a² + b²
c² = 10² + 1.1²
c = √101.21
c = 10.0603180864
c = 10.1 miles
plane's path = 10.1 miles
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