The vertical height of the given plane is 4.9 m.
The given parameters:
- speed of the object at the bottom of the ramp, v = 9.8 m/s
The vertical height of the plane is calculated by applying principle of conservation of mechanical energy as follows;
[tex]P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\h = \frac{v^2}{2g} \\\\h = \frac{9.8 \times 9.8}{2 \times 9.8} \\\\h = 4.9 \ m[/tex]
Thus, the vertical height of the given plane is 4.9 m.
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