Using proportions, it is found that there would be 500,000 mites.
- This question is solved by proportions, using a rule of three.
- Each dust mite has a length of [tex]2.5 \times 10^{-4}[/tex] m. How many dust mites could there be in a line of [tex]1.25 \times 10^2[/tex] m long?
The rule of three is:
1 dust mite - [tex]2.5 \times 10^{-4}[/tex] m.
x dust mites - [tex]1.25 \times 10^2[/tex] m
Applying cross multiplication:
[tex]2.5 \times 10^{-4}x = 1.25 \times 10^2[/tex]
[tex]x = \frac{1.25 \times 10^2}{2.5 \times 10^{-4}}[/tex]
[tex]x = 500000[/tex]
There would be 500,000 mites.
A similar problem is given at https://brainly.com/question/24372153
