Answer:
2,100 $28 tickets were sold, and 3,900 $40 tickets were sold!
Step-by-step explanation:
So, we need to write two equations in order to solve this:
We will think of 28 dollar tickets as x, 40 dollar tickets as y.
Now lets make those equations:
[tex]x + y = 6,000[/tex]
and
[tex]28x+40y = 193,200[/tex]
Now, to solve for x and y, lets set a value for x or y. In this case I will set the value of y:
I will do this by taking [tex]x + y = 6,000[/tex], and subtracting x to the other side, to get y alone:
[tex]y = 6,000 - x[/tex]
Now lets plug in y to our second equation:
[tex]28x + 40(6,000-x) = 193,2000[/tex]
=
[tex]28x+240,000-40x = 193,200[/tex]
Now combining like terms and solving for x we get:
[tex]-12x + 240,000 = 193,200[/tex]
=
[tex]-12x = -46,800[/tex]
=
[tex]x=3,900[/tex]
Now that we know x, lets solve for y by plugging into our first equation!
[tex]3,900 + y = 6,000[/tex]
=
[tex]y = 2,100[/tex]
So now we know that our answer is:
2,100 $28 tickets were sold, and 3,900 $40 tickets were sold!
Hope this helps! :3
