Respuesta :
[tex]^{n}P_{r}=\dfrac{n!}{(n-r)!}\\\\\implies ^{9}P_5 = \dfrac{9!}{(9-5)!} =\dfrac{9!}{4!} = 15120[/tex]
The answer is D.
[tex]^{n}P_{r}=\dfrac{n!}{(n-r)!}\\\\\implies ^{9}P_5 = \dfrac{9!}{(9-5)!} =\dfrac{9!}{4!} = 15120[/tex]
The answer is D.