Tensile stress in a thin wall spherical shell is given by
σ = ( p r ) /2t
This is the type of stress that involves pulling out. it is the opposite of compressive stress.
The tensile stress, σ at the circumference of the shell is the hoop stress. The value equals that of pressure acting on the area.
Therefore:
σ * 2πr * t = p * πr^2
where
2πr = circumference of a circle
πr^2 = area of a circle
p = internal pressure
t = thickness
σ * 2πr * t = p * πr^2
σ = ( p r ) /2t
Read more Tensile stress here:
https://brainly.com/question/25748369