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5. How much water would need to be added to 750 mL of a 2.8 M HCl solution to
make a 1.0 M solution?

6. If I add 25 mL of water to 125 mL of a 0.15 M NaOH solution, what will the molarity of the diluted solution be?

7. If I add water to 100 mL of a 0.15 M NaOH solution until the final volume is 150 mL, what will the molarity of the diluted solution be?

8. How much 0.05 M HCl solution can be made by diluting 250 mL of 10 M HCl?

9. I have 345 mL of a 1.5 M NaCl solution. If I boil the water until the volume of the solution is 250 mL, what will the molarity of the solution be?

10.
How much water would I need to add to 500 mL of a 2.4 M KCl solution to make a 1.0 M solution

please help me

Respuesta :

The values of molarity and volumes for the given questions are  2,100 mL, 0.75 M, 0.1 M, 50,000 mL, 2.07 M and 1,200 mL respectively.

What is the relation between the molarity & volume of solution?

Relation between the molarity and volume of the solution will be shown by the following equation:
M₁V₁ = M₂V₂, where

M₁ & V₁ is the molarity and volume of one solution whereas M₂ & V₂ are the molarities and volume of the another solution.

  • Required volume of water needed to add at 750 mL of a 2.8 M HCl solution to make a 1.0 M solution will be calculated by using the above formula:

V₂ = (750)(2.8) / (1) = 2,100 mL

  • Required molarity of diluted solution obtained on adding 25 mL of water to 125 mL of a 0.15 M NaOH solution will be calculated by using the above formula:

M₂ = (0.15)(125) / (25) = 0.75 M

  • Required molarity of diluted solution obtained on adding 100 mL of a 0.15 M NaOH solution until the final volume is 150 mL will be calculated by using the above formula:

M₂ = (100)(0.15) / (150) = 0.1 M

  • Required volume of HCl of 0.05M HCl can be made by diluting 250 mL of 10 M HCl will be calculated by using the above formula:

V₂ = (10)(250) / (0.05) = 50,000 mL

  • Molarity of the resultant solution is:

M₂ = (1.5)(345) / (250) = 2.07 M

  • Required volume of water to add on KCl solution is:

V₂ = (2.4)(500) / (1) = 1,200 mL

Hence required values of molarity and volume are 2,100 mL, 0.75 M, 0.1 M, 50,000 mL, 2.07 M and 1,200 mL respectively.

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