1066.7 ml of the stock solution must start with, preparing 2.00 L of a 0.800 M NaNO3 solution.
Volume is the space occupied by a three-dimensional object.
By the formula [tex]\rm M_1V_1= M_2V_2[/tex]
M1 is the initial molarity, 1.5 M
M2 is the final molarity, 0.800 M
V1 is the initial volume
V2 is the final volume, 2.00 L
Putting the values in the equation
[tex]\rm 1.5\;M \times V_1= 0.800\;M \times 2.00\;L\\\\V_1 = \dfrac{ 0.800\;M \times 2.00\;L}{1.5\;M} = 1066.7\;ml[/tex]
Thus, the initial volume is 1066.7 ml
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