Answer:
Step-by-step explanation:
let y=f(x)
y=10x-10
flip x and y
x=10y-10
10 y=x+10
[tex]y=\frac{1}{10}x+1\\f^{-1}(x)=\frac{1}{10}x+1\\(fof^{-1}{x})=f(f^{-1}(x))=f(\frac{1}{10} x+1)=10(\frac{1}{10} x+1)-10=x+10-10=x\\(fof^{-1})(-10)=-10[/tex]
The value of (f o f ^-1)(-10) is -10
The function is given as:
[tex]f(x) = 10x -10[/tex]
To calculate (f o f ^-1)(-10), we make use of the following equation
(f o f ^-1)(x) = x
Substitute -10 for x
(f o f ^-1)(-10) = -10
Hence, the value of (f o f ^-1)(-10) is -10
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