The reactants that will form products will be [tex]2CuI_2 + Br2[/tex].
Elements at higher positions in the activity series will be able to displace those in lower positions in solutions.
Thus:
[tex]2CuI_2 + Br2 --- > 2CuBr +2 I_2[/tex] because Br is higher than I in the activity series.
Cl cannot displace F in [tex]Cl2 + AlF_3[/tex] because F is higher than Cl in the activity series.
Also, Cl is higher than Br in the activity series, thus, the reaction [tex]Br_2 + NaCl[/tex] cannot form products.
I cannot displace F, thus, [tex]CuF_2 + I_2[/tex] cannot form products.
More on activity series can be found here: https://brainly.com/question/13934381
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