[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
As we know, all sides of a Rhombus are equal to each other ~ so we can conclude that :
[tex]\qquad \sf \dashrightarrow \:4x - 16 = 2x + 6[/tex]
[tex]\qquad \sf \dashrightarrow \:4x - 2x = 6 + 16[/tex]
[tex]\qquad \sf \dashrightarrow \:2x = 22[/tex]
[tex]\qquad \sf \dashrightarrow \:x = 22 \div 2[/tex]
[tex]\qquad \sf \dashrightarrow \:x = 11[/tex]
Now, plug in the value of x in any equation to get the side length of rhombus ~
[tex]\qquad \sf \dashrightarrow \:2x + 6[/tex]
[tex]\qquad \sf \dashrightarrow \:2(11) + 6[/tex]
[tex]\qquad \sf \dashrightarrow \:22 + 6[/tex]
[tex]\qquad \sf \dashrightarrow \:28 \: \: units[/tex]
Side PS = Side QR = 28 units
