52.66 grams of acetylene are in the tank.
PV=nRT is the formula for ideal gases, where P is the pressure and R is the constant and T is the temperature (P is 1.39 atm in this case)
Volume = 35.0 L
Gas constant = 0.08206 L.atm/K.mole
Temperature = 20.0 °C = 293 °C
We also know that we can apply the formula ;
Number of mole(n) = [tex]\frac{MmPV}{RT}[/tex]
m = ( 26.04 × 1.39 × 35 )/ (0.08206 × 293.15)
m = 52.66 g
Thus, the mass is 52.66 grams.
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