Respuesta :
Multiply the first coefficient (3) and the last term (2) to get 3*2 = 6
We need to find two numbers that
a) multiply to 6
AND
b) add to -5 (middle coefficient)
Such two numbers are -3 and -2
-3 times -2 = 6
-3 plus -2 = -5
So we can break up the -5x into -3x-2x and then factor by grouping
--------------
3x^2-5x+2
3x^2-3x-2x+2
(3x^2-3x)+(-2x+2)
3x(x-1)+(-2x+2)
3x(x-1)-2(x-1)
(3x-2)(x-1)
So the two factors are (3x-2) and (x-1)
The answers are A and C
We need to find two numbers that
a) multiply to 6
AND
b) add to -5 (middle coefficient)
Such two numbers are -3 and -2
-3 times -2 = 6
-3 plus -2 = -5
So we can break up the -5x into -3x-2x and then factor by grouping
--------------
3x^2-5x+2
3x^2-3x-2x+2
(3x^2-3x)+(-2x+2)
3x(x-1)+(-2x+2)
3x(x-1)-2(x-1)
(3x-2)(x-1)
So the two factors are (3x-2) and (x-1)
The answers are A and C
The factor of the equation [tex]3x^{2} -5x+2 = 0[/tex] is [tex]x = \frac{3}{2} , 1[/tex].
Multiply the first coefficient 3 and the last term 2 to get 3×2 = 6.
Given ,
Quadratic equation = [tex]3x^{2} -5x+2[/tex]
We have to find,
The two factors can be multiplied together to make this trinomial .
According to the question,
[tex]3x^{2} - 5x + 2 = 0\\3x^{2} - 3x-2x+2 = 0\\3x ( x - 1) -2 (x-1) = 0\\(3x-2) (x-1) = 0 \\[/tex]
Then, 3x - 2 = 0
3x = 2
[tex]x = \frac{3}{2}[/tex]
And x - 1 = 0
x = 1
The factor of the equation [tex]3x^{2} -5x+2 = 0[/tex] is [tex]x = \frac{3}{2} , 1[/tex].
Multiply the first coefficient 3 and the last term 2 to get 3×2 = 6.
For more information about Quadratic equation click the link given below.
https://brainly.com/question/24794042