Complete the factorization of 3x2 – 5x + 2.

Which two factors can be multiplied together to make this trinomial?

(x – 2)

A) (x – 1)

B) (x + 1)

C) (3x – 2)

D) (3x + 2)

Respuesta :

Multiply the first coefficient (3) and the last term (2) to get 3*2 = 6

We need to find two numbers that

a) multiply to 6
AND
b) add to -5 (middle coefficient)

Such two numbers are -3 and -2
-3 times -2 = 6
-3 plus -2 = -5

So we can break up the -5x into -3x-2x and then factor by grouping

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3x^2-5x+2

3x^2-3x-2x+2

(3x^2-3x)+(-2x+2)

3x(x-1)+(-2x+2)

3x(x-1)-2(x-1)

(3x-2)(x-1)

So the two factors are (3x-2) and (x-1)

The answers are A and C

The factor of the equation [tex]3x^{2} -5x+2 = 0[/tex] is [tex]x = \frac{3}{2} , 1[/tex].

Multiply the first coefficient 3 and the last term 2 to get 3×2 = 6.

Given ,

Quadratic equation = [tex]3x^{2} -5x+2[/tex]

We have to find,

The two factors can be multiplied together to make this trinomial .

According to the question,

[tex]3x^{2} - 5x + 2 = 0\\3x^{2} - 3x-2x+2 = 0\\3x ( x - 1) -2 (x-1) = 0\\(3x-2) (x-1) = 0 \\[/tex]

Then, 3x - 2 = 0

         3x = 2

         [tex]x = \frac{3}{2}[/tex]

And x - 1 = 0

       x = 1

The factor of the equation [tex]3x^{2} -5x+2 = 0[/tex] is [tex]x = \frac{3}{2} , 1[/tex].

Multiply the first coefficient 3 and the last term 2 to get 3×2 = 6.

For more information about Quadratic equation click the link given below.

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