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A sample of tin (Cp = 0.227 J/g•°C) is placed in a freezer. Its temperature decreases from 15.0°C to −10.0°C as it releases 543 J of energy. What is the mass of the sample? Round your answer to three significant figures.

Respuesta :

We know, Q = m.c.Δt
m = Q / c.Δt

Here, Q = 543 J
c = 0.227 J/g C
Δt = 15-(-10) = 25 C

Substitute their values,
m = 543 / 0.227 * 25
m = 543 / 5.675
m = 95.68 g

In short, Your Answer would be 95.68 gram

Hope this helps!
mahima6824soni

The mass of the sample is 95.7 grams.

What is mass?

The average mass of an element's atoms, is expressed in atomic mass units.

Calculation:

Specific heat = Q = m.c.Δt

Given, Q = 543 J

c = 0.227 J/g CΔ

Δt = 15-(-10) = 25 C

where 15.0° C - 10.0 °C is the temperature difference

Now, from the equation

[tex]\bold{m = \dfrac{543}{0.227} \times 25}[/tex]

Mass = 95.7 grams.

Thus, the mass of the sample is 95.7 grams.

Learn more about mass, here:

https://brainly.com/question/15959704

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