The Henderson-hasselbalch equation for a propanoic acid solution is expressed as [A-]/[HA] = 2.7.
It is expressed as:
pH = pKa + log([A-]/[HA].
where,
[A-] is molar concentration of conjugate base and
[HA] is molar concentration of weak acid.
Given,
pH = 5.30
Substitute the value in the Henderson Hasselbalch equation
5.30 = 4.874 + log[A-]/ [HA]
log[A-]/[HA] = 5.30 - 4.874
[A-]/[HA] = 10^ 0.426
[A-]/[HA] = 2.7
Thus from the conclusion we can say that The henderson-hasselbalch equation for a propanoic acid solution is expressed as [A-]/[HA] = 2.7.
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