the resistance of the circuit containing 110V and 1.42A current will be 78.57 ohm.
To find the answer, we need to know more about the Ohm's law.
[tex]V[/tex]∝ [tex]I[/tex]
[tex]V=IR[/tex]
where, R is the proportionality constant called resistance of the circuit.
[tex]R=\frac{V}{I} =\frac{110}{1.40}=78.57Ohm[/tex]
Thus, we can conclude that, the resistance of the circuit containing 110V and 1.42A current will be 78.57 ohm.
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