The self inductance can be calculated as 4.444 Henry.
The inductor will store energy = 20 joule,
current = 3 ampere.
The current carrying conductor which allows or opposes the change of flow of current is known as self-inductance. The rate of change of current can also be given through self inductance.
Formula can be given for the energy in the inductor as,
E = 1 / 2 × L × I² joule.
where as, E - Energy
L - Inductance
I - Current flowing through the coil.
The equation can be rearranged as,
L = 2 E/ I²
= 2 × 20 / 3²
= 40 / 9
Hence, L = 4.4444 Henry
Learn more about energy in inductors,
https://brainly.com/question/28030901
#SPJ4
