There are 3 moles of [tex]H_{2} O[/tex] are produced in neutralization when 1. 5 mole of [tex]Mg(OH)_{2}[/tex] reacts with [tex]H_{2} SO_{4[/tex]
The neutralization reaction between magnesium hydroxide and sulfuric acid is given as,
[tex]Mg(OH)_{2} + H_{2} SO_{4[/tex] → [tex]MgSO_{4} + 2H_{2} O[/tex]
from above chemical equation , we can conclude the molar ratio = 1:2
It means two moles of water molecule is produce from one mole of magnesium hydroxide.
So, number of moles of water molecules produced from 1. 5 mole of magnesium hydroxide = 1. 5 mole× 2 = 3 moles
Therefore, number of moles of water molecules produced from 1. 5 mole of magnesium hydroxide is 3 moles.
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