6 V drop occurs across the 6 ohm resistor in the parallel circuit diagram. The correct answer is C.
Since this parallel combination is connected with a cell, the potential difference through each resistor will be 6 volts. Now using I=V/R,
Current through 3 ohm resistor = 6/3 = 2 V
Current through 6 ohm resistor = 6/6 = 1 V
And the total current will be the sum of individual current in each resistor using Kirchoff’s junction law, Total current = 3 ampere
Since it is parallel combination the current passing across two resistors can differ but the voltage drop will remain the same.
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