what, roughly, is the percent uncertainty in the volume of a spherical beach ball whose radius is r

The experimenter's best guess about how much an experimental parameter might deviate from its "actual value" is called uncertainty.
The elements determining the uncertainty accumulate at the time of each measurement of a physical quantity, and indeed the uncertainty of both the volume is dictated by that of the uncertainty of something like the method and also the uncertainty of both the density calculation.

Given,

r = 0.84 ±0.04 M

r = 0.04 M

V = [tex]\frac{4}{3} \pi r^3[/tex]

Taking log of both sides and solving,

log v = log[tex]\frac{4}{3} \pi[/tex] + 3 log r

Differentiating both side,

[tex]\frac{dv}{v} =\frac{3dr}{r}[/tex]

[tex]\frac{dv}{v} *100=\frac{3dr}{r}*100[/tex]

= 14.29%

Percent uncertainty in the volume of a spherical beach ball whose radius is r is 14.29%.

Learn more about uncertainty here:

https://brainly.com/question/3998745

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