After solving the expressions we get the value for each of it as:
a. 1/108
b. 7/18
Given:
a. 12x⁰(x⁻⁴)
Apply the multiplication property of exponents.
when variables multiply, the powers are added.
12x⁰⁻⁴
12x⁻⁴
substitute the value of x = 6 in the above term.
12(6)⁻⁴
12 × 1/6⁴
12 × 1/1296
1/108
b. 14(x⁻²)
The algebraic technique for resolving simultaneous linear equations is called the substitution method. The value of a variable from one equation is substituted in the second equation in this procedure, as the name implies.
directly substitute the value of the x in the expression.
14(6)⁻²
14 × 1/6²
14 × 1/36
7/18
hence after evaluating expressions we get the values as 1/108 and 7/18.
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