Respuesta :

[tex]\begin{gathered} \text{The equation of a straight line is} \\ y-y_1=\text{ }\frac{y_2-y_1}{x_2-x_1}(x-x_1) \end{gathered}[/tex]

Step 2 : Define parameters

[tex]\begin{gathered} y_1=0 \\ y_2=1 \\ x_1=-5 \\ x_2=\text{ -3} \end{gathered}[/tex]

Step 3: Substitute the parameters into the equation

[tex]\begin{gathered} \text{slope}=\text{ }\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{1-0}{-3-(-5)} \\ \text{slope = }\frac{1}{-3+5}=\frac{1}{2} \\ \text{slope}=\text{ }\frac{1}{2}\text{ or 0.5} \end{gathered}[/tex]