Two players ran two different routes, player one ran 19 post routes and 21 slant routes and a total of 508 yards, similarly the player two ran 30 post routes and 20 slant routes and a total distance of 710 yards, following system of linear equations describe this situation:
[tex]\begin{gathered} 19P+21S=508\rightarrow(1) \\ \\ 30P+20S=710\rightarrow(2) \end{gathered}[/tex]The solution to the (1) and (2) is as follows:
[tex]\begin{gathered} S=x \\ P=y \\ \\ \therefore\rightarrow \\ 19y+21x=508 \\ 30y+20x=710 \end{gathered}[/tex]The following plot shows the solution:
Therefore the answer is:
[tex]\begin{gathered} S=x=7yd\rightarrow(I) \\ \\ P=y=19yd\rightarrow(II) \end{gathered}[/tex](I) is the length of the slant route and (II) is the length of the post route.