[tex]A)\text{Area}=72cm^2[/tex][tex]B)\text{Area}_t=68m^2[/tex]
Explanation
Step 1
find the area:
Arectanglewithlength6cmandwidth12cm.
the area of a rectangle is given by:
[tex]\begin{gathered} \text{Area}=\text{length}\cdot\text{width} \\ \end{gathered}[/tex]
so, Let
length=6 cm
width=12 cm
replace in the formula
[tex]\begin{gathered} \text{Area}=\text{length}\cdot\text{width} \\ \text{Area}=6\text{ cm }\cdot\text{ 12 cm} \\ \text{Area}=72cm^2\text{= 72 square centimeters} \end{gathered}[/tex]
Step 2
find the area:
Atrianglewithbase17metersandheight8meter:
the area of a triangle is given by:
[tex]\begin{gathered} \text{Area}_t=\frac{base\cdot heigth}{2} \\ \end{gathered}[/tex]
Let
base= 17 m
heigth= 8 m
replace,
[tex]\begin{gathered} \text{Area}_t=\frac{base\cdot heigth}{2} \\ \text{Area}_t=\frac{17\text{ m}\cdot\text{ 8 m}}{2} \\ \text{Area}_t=\frac{136m^2}{2} \\ \text{Area}_t=68m^2=68\text{ square meters} \end{gathered}[/tex]
I hope this helps you
