Given data
*The given distance is r = 5.0 cm = 0.05 m
*The given charge is
[tex]q=6.6\mu C=6.6\times10^{-6}\text{ C}[/tex]The formula for the electric field strength is given as
[tex]E=\frac{kq}{r}[/tex]*Here k is the Coulomb constant
Substitute the values in the above expression as
[tex]\begin{gathered} E=\frac{(9\times10^9)(6.6\times10^{-6})}{0.05} \\ =1.18\times10^6\text{ N/C} \end{gathered}[/tex]