Fire towers A and B are located 10 miles apart. They usethe direction of the other tower as0°. Rangers at fire tower A spots a fire at 42°, andrangers at fire tower B spot the same fireat 64º. How far from tower A is the fire to the nearesttenth of a mile?10 miles64"Tower ATower B

Fire towers A and B are located 10 miles apart They usethe direction of the other tower as0 Rangers at fire tower A spots a fire at 42 andrangers at fire tower class=

Respuesta :

ANSWER:

9.4 miles

STEP-BY-STEP EXPLANATION:

The distance from tower A to the fire can be calculated using the law of sines.

The law of sine is the following:

[tex]\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}[/tex]

In this case the corresponding values would be:

a = 10 miles

The angle A we do not know it, we must calculate it, knowing that the sum of all the angles within a triangle is equal to 180°, therefore:

[tex]\begin{gathered} A+B+C=180 \\ A=180-B-C \\ A=180-42-64 \\ A=74\degree \end{gathered}[/tex]

A = 74°

B = 64°

b = distance from tower A to the fire

Replacing and solving:

[tex]\begin{gathered} \frac{10}{\sin74}=\frac{b}{\sin 64} \\ b=10\cdot\frac{\sin 64}{\sin 74} \\ b=9.4\text{ miles} \end{gathered}[/tex]

The distance from tower A to the fire is equal to 9.4 miles.