Given:
The mass is m1 = m2 = 3.24 kg
The distance between them is r = 3.88 m
The charge on each mass is q1 = q2 = 96.852 micro Coulombs
To find the acceleration of the mass.
Explanation:
The acceleration can be calculated by the formula
[tex]a=\frac{F}{m}[/tex]The force can be calculated by the formula
[tex]F=\frac{kq1q2}{r^2}[/tex]Here, k is the Coulomb's constant whose value is
[tex]k=\text{ 9}\times10^9\text{ N m}^2\text{ /C}^2[/tex]
On substituting the values, the force will be
[tex]\begin{gathered} F=\frac{9\times10^9\times(96.852\times10^{-6})^2}{(3.88)^2} \\ =5.61\text{ N} \end{gathered}[/tex]The acceleration will be
[tex]\begin{gathered} a=\frac{5.61}{3.24} \\ =1.73\text{ m/s}^2 \end{gathered}[/tex]Thus, the acceleration of each mass is 1.73 m/s^2