SOLUTION
The table below would be helpful in solving the question
Probability of getting food from restaurant A becomes
[tex]\begin{gathered} \frac{expected\text{ outcome for A}}{total\text{ outcome }} \\ \frac{350}{1,115} \end{gathered}[/tex]
Probability of getting food that is not from restaurant A becomes
1 - Probability of getting food from restaurant A
[tex]\begin{gathered} 1-\frac{350}{1115} \\ =\frac{153}{223} \\ =0.68609865 \\ =0.686 \end{gathered}[/tex]
Hence the answer is 0.686
