We have
[tex]f(x)=log_3(x)[/tex]and
[tex]g(x)=log_3(9x)[/tex]We rewrite g(x)
[tex]g(x)=\frac{log(x)+log(9)}{log\left(3\right)}[/tex][tex]g(x)=\log_3\left(x\right)+2[/tex]As we can see we have a vertical translation 2 units up
ANSWER
vertical translation 2 units up