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These data are the number of on campus burglaries reported in a given year fornine western Pennsylvania universities16 11 3 16 9 7 14 6 16For the above data set find the mean, median, midrange, and mode. Round to one decimal place if necessary

These data are the number of on campus burglaries reported in a given year fornine western Pennsylvania universities16 11 3 16 9 7 14 6 16For the above data set class=

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Answer:

Mean: 10.9

Median: 11

Midrange: 9.5

Mode: 16

Explanation:

The mean is the sum of all the values of the data, divided by the number of data.

In this case, the number of data is 9, the total universities we have the stats.

The sum of all burglaries is:

[tex]16+11+3+16+9+7+14+6+16=98[/tex]

The mean is:

[tex]\frac{98}{9}\approx10.888[/tex]

To one decimal: the mean is 10.9

THe median is the value that falls in the middle of the data, ordered in ascending form.

The ordered data is

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