ANSWER:
[tex]x=\pi n, \frac{3\pi}{2}+2\pi n[/tex]
EXPLANATION"
Given:
[tex]\sin x(\sin x+1)=0[/tex]
Having solved Step 1 and Step 2 as seen above, we can go ahead and write the solutions of the equation as seen below;
[tex]\begin{gathered} If\text{ }\sin x=0 \\ \therefore x=\pi \\ \\ If\text{ }\sin x=-1 \\ then\text{ }x=\frac{3\pi}{2} \\ \\ So\text{ }the\text{ }solution\text{ }will\text{ }be; \\ x=\pi n,\frac{3\pi}{2}+2\pi n \end{gathered}[/tex]
