We have a change of pressure and temperature. To solve and find the new pressure we will assume that the volume and moles of the gas remain constant, therefore we can apply Gay-Lussac's law which tells us:
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
Where,
P1 is the initial pressure of the gas, 954atm
T1 is the temperature of the gas, 728K
T2 is the final temperature, 951K
P2 is the final pressure, =?
We clear P2 and replace the known data:
[tex]\begin{gathered} P_2=\frac{P_1}{T_1}\times T_2 \\ P_2=\frac{954atm}{728K}\times951K=1246atm \end{gathered}[/tex]
Answer: The new pressure will be 1246atm
