Answer:
Did not multiply the numerator by the radical
Explanation:
The hypotenuse of a 45-45-90 triangle is equal to the leg times √2.
In this case, the leg is x and the hypotenuse is 6, so we have the following equation
hypotenuse = leg √2
6 = x √2
To solve for x, we get
[tex]\begin{gathered} x\sqrt{2}=6 \\ \\ x=\frac{6}{\sqrt{2}} \end{gathered}[/tex]
Then, we need to multiply the numerator and denominator by √2, so
[tex]x=\frac{6}{\sqrt{2}}\cdot\frac{\sqrt{2}}{\sqrt{2}}=\frac{6\sqrt{2}}{(\sqrt{2})^2}[/tex]
Therefore, the solution is equal to
[tex]x=\frac{6\sqrt{2}}{2}=3\sqrt{2}[/tex]
Therefore, the error in the process was that they did not multiply the numerator by the radical
