Solution.
Given the triangle
[tex]\begin{gathered}Using sine rule,
[tex]\frac{a}{sinA}=\frac{b}{sinB}=\frac{c}{sinC}[/tex][tex]\begin{gathered} \frac{a}{sin35}=\frac{32}{sin77} \\ a=\frac{32\text{ x sin35}}{sin77} \\ a=18.84 \\ a=18.8(nearest\text{ tenth\rparen} \end{gathered}[/tex][tex]\begin{gathered} \frac{a}{sinA}=\frac{c}{sinC} \\ \frac{18.84}{sin35}=\frac{c}{sin68} \\ \end{gathered}[/tex][tex]\begin{gathered} c=\frac{18.84\text{ x sin68}}{sin35} \\ c=30.45 \\ c=30.5(nearest\text{ tenth\rparen} \end{gathered}[/tex]